Question

find the quadratic polynomial where zeroes are 7+√3,7-√3

Answer 1

$\alpha = 7 + \sqrt{3} \\ \beta = 7 - \sqrt{3}$
We know that,
$\alpha + \beta = \frac{ - b}{a} \\ \alpha \beta = \frac{c}{a}$
So,
b = (- 49)
a = 1
c = 46.

By general Quadratic equation,
$a {x}^{2} + bx + c = 0$
Quadratic equation is:-
${x}^{2} - 49x + 46$





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