find the quadratic polynomial whose 2 zeros are 1/2 and -1/8
Answers
Answered by
0
Answer:
16x² - 6x - 1 = 0
Step-by-step explanation:
sum of zeroes = 1/2 + -1/8 = 3/8
product of zeroes = 1/2 * -1/8 = -1/16
quadratic eqn : x²- (sum of zeroes)*x + (product of zeroes) = 0
ie. x²- 3/8x + -1/16 = 0
LCM = 16
16x² - 16*3/8x + 16*-1/16 = 0
16x² - 6x - 1 = 0
mark as brainliest...
Similar questions