Question

Find the quadratic polynomial whose one zero is 3 - √3 and product of zeroes is 4.​

Answer 1

Answer:

1÷3-√3((3-√3)x²-10x+4(3-√3))

Step-by-step explanation:

let roots be A and B

A=3-√3

Now, AB=4

       B=4\(3-√3)

      Now, A +B = 10\(3-√3)

Polynomial= x²-(A+B)x+AB

         Put the value and find the lcm .

Answer 2

Sum of Zeroes = 3 - √3

Product of Zeroes = 4

If one Zero is 3 - √3, then other must be 3 + √3.

Sum of Zeroes = (3 - √3 + 3 + √3) = 6

Product of Zeroes = 4

We Know that the Formula to find Quadratic Equation f(x) is

f(x) = K[x² - (α + β)x + α.β]

= K[x² - 6x + 4]

= K[x² - 6x + 4]

= x² - 6x + 4 [ ∵ K is a Constant]

The quadratic equation is x² - 6x + 4.