find the quadratic polynomial whose sum and product of zeros are - 3 and 2 respectively
Answers
Answered by
15
sum of roots = -3
product of roots =2
we know,
quadratic equation : x² -(sum of roots )x + product of roots
so, quadratic equation,
x² - (-3)x + 2
⇒x² + 3x + 2
product of roots =2
we know,
quadratic equation : x² -(sum of roots )x + product of roots
so, quadratic equation,
x² - (-3)x + 2
⇒x² + 3x + 2
Answered by
3
given alpha+beta =-3
and alpha ×beta=2
now for making a quadratic eqn. the formula is
= p(x)=k{xsquare -(alpha+beta)x +(alpha×beta)}
= p (x)=k{xsquare- (-3)x + 2}
=p(x)=k{xsquare + 3x + 2}
thnq hope it will help you
and alpha ×beta=2
now for making a quadratic eqn. the formula is
= p(x)=k{xsquare -(alpha+beta)x +(alpha×beta)}
= p (x)=k{xsquare- (-3)x + 2}
=p(x)=k{xsquare + 3x + 2}
thnq hope it will help you
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