Find the quadratic polynomial whose sum of zeroes is 10 and the product is -39.
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Answered by
3
Answer:
x2-10x-39 is the quadratic Equation
Answered by
5
Answer:
let px²+qx+r=0 is a quadratic equation.
let a and b are two zeroes of this equation.
As per question,
a+b=(-q/p)=10
So q/p=(-10).......(i)
ab=(r/p)=(-39).......(ii)
Now dividing p on both sides of quadratic equation we get,
x²+(q/p)x+(r/p)=0........(iii)
Putting the values of equations (i) and (ii) in equation (iii) we get,
x²-10x-39=0
This is the required equation.
If my answer satisfies you then give me thanks.
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