Question

Find the quadratic polynomial whose sum of zeroes is 2 and
product of zeroes is -3.

Answer 1

Answer:

$sum \: of \: zeros \: ( \alpha + \beta ) = 2$

$product \: of \: zeros \: ( \alpha \beta ) = - 3$

$p(x) = {x}^{2} - ( \alpha + \beta )x + \alpha \beta$

${x}^{2} - (2)x + ( - 3)$

${x}^{2} - 2x - 3$

The polynomial is = x^2 - 2x - 3

Ans. x^2 - 2x - 3

Hope it helps.