Find the quadratic polynomial whose zeroes are 1/2 & -4
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Given :- Find the quadratic polynomial whose zeroes are 1/2 & (-4) ?
Answer :-
we know that, the quadratic polynomial is given by,
- x² - (sum of zeroes)x + product of zeroes = 0
so, putting values we get,
→ x² - [(1/2) + (-4)] + * (1/2) * (-4) = 0
→ x² - [(1 - 8)/2]x + (-2) = 0
→ x² - (-7/2)x - 2 = 0
→ (2x² + 7x - 4)/2 = 0
→ 2x² + 7x - 4 = 0 (Ans.)
Learn more :-
JEE mains Question :-
https://brainly.in/question/22246812
. Find all the zeroes of the polynomial x4
– 5x3 + 2x2+10x-8, if two of its zeroes are 4 and 1.
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