find the quadratic polynomial whose zeroes are 1/4 and -1/5
Answers
Answer:
sum of zeroes = 1/4 - 1/5 = 5-4/20 = 1/20. (bcoz LCM of 5 and 4 is 20)
product of zeroes = 1/4 * (-1/5) = -1/20
so polynomial formed:
x² - (1/20)x -1/20
Hope this helps ☺️
Step-by-step explanation:
Given:-
zeroes are 1/4 and -1/5
To find:-
find the quadratic polynomial whose zeroes are 1/4 and -1/5
Solution:-
Given zeroes are 1/4 and -1/5
Let the zeores be α and β
α = 1/4
β = -1/5
Sum of the zeores = α + β
=(1/4)+(-1/5)
LCM of 4 and 5 = 20
=> (5-4)/20
=> 1/20
Product of the zeroes =αβ
=> (1/4)(-1/5)
=>-1/20
we know that
α and β are the zeores then the quadratic polynomial is
K[x^2-(α + β)x +αβ]
=> K[x^2-(1/20)x+(-1/20)]
=>K[(20x^2-x-1)/20]
If K = 20 then
The required Polynomial = 20x^2-x-1
Answer:-
The quadratic polynomial for the given zeroes is
20x^2-x-1
Used formula:-
α and β are the zeores then the quadratic polynomial is
K[x^2-(α + β)x +αβ]