Find the quadratic polynomial
whose zeroes are
-2√3 and -√3/2? Answer Fast
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Any polynomial can be written as
a x^2 + bx + c, in this of your a= 1, then your b = negative of sum of both roots and c = multiplication of both roots.
So, c = (-2 root 3) * ( -root 3/2)
c = 3 and b = 2√3 + √3/2.
So, our polynomial is
x^2 + (2√3 + √3/2) x + 3. You can simplify it further if required.
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