Question

find the quadratic polynomial whose zeroes are -2 and 5​

Answer 1

x^2-(-2+5)+(-2*5)=0
=x^2-3x-10=0

Answer 2

$\green★\:\alpha \: = - 2 \\ \\\green★\:\beta = 5$

${x}^{2} - ( \alpha + \beta) + \alpha \beta \\ \\ \implies {x}^{2} - ( - 2 \: + 5)x + 2 \times - 5 \\ \\ \implies {x}^{2} -( 3)x - 10 \\ \\ \implies \red{ {x}^{2} - 3x - 10}\\\\\\{x}^{2} - 3x - 10\\\\{x}^{2} - 5x+2x - 10\\\\x(x-5)+2(x-5)\\\\(x+2)(x-5)=0\\\\x= - 2\:\:\:x= 5$