Find the quadratic polynomial whose zeroes are 2+root 3 and 2-root3
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3
x^2-(sum of roots)x+(product of roots)
x^2-4x+(4-3)
x^2-4x+1
x^2-4x+(4-3)
x^2-4x+1
Answered by
9
Answer:
Quadratic equation =
X^2 - (sum of the zeroes)x + (product of the zeroes)
Sum= 2 + root3 + 2 - root3
=4
Product = (2 + root3)(2-root3) = 4-3 = 1
So quadratic equation is
X^2 - 4x + 1
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