What is the equation of a line, in point-slope form, that passes through (−8, 1) and has a slope of 56
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y-y1=m(x-x1)
y-1=56(x+8)
y-1=56x+448
56x-y+449
I HOPE THIS WILL HELP U
y-1=56(x+8)
y-1=56x+448
56x-y+449
I HOPE THIS WILL HELP U
Answered by
0
(y-1)=56(x-(-8))
y-1=56(x+8)
y-1=56x+448
56x-y+449=0
y-1=56(x+8)
y-1=56x+448
56x-y+449=0
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