Question

Find the quadratic polynomial whose zeroes are 3+2√2 and 3-2√2

Answer 1

Answer:

x square-6x+1

Step-by-step explanation:

pls refer my attachment...

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Answer 2

Answer:

sum of zeroes=(3+2√2+3-2√2)=-b/a

=6 = -b/a

a=1 and b= -6

now product of zeroes=c/a

(3+2√2) (3-2√2)

9-8=1

1=c/a

=c=1

now the general form of a quadratic polynomial is

ax^2+bx+c

put the values of a,b,c we get

x^2-6x+1

this is the required quadratic polynomial

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