Question

Find the quadratic polynomial whose zeroes are 3 snd -7/5

Answer 1

$Sum=3+(\frac{-7}{5})\\ \\=(\frac{15-7}{5} )\\\\= \frac{8}{5}$

$Product=\frac{3*(-7)}{5}\\\\=\frac{3*(-7)}{5} \\\\= \frac{-21}{5}$

Required Polynomial = x² - (Sum of zeroes) x + Product of zeroes

$0= x^{2}-( \frac{8}{5} )x + (\frac{-21}{5} )\\\\0= x^2-\frac{8x}{5}-\frac{21}{5}\\ \\0= 5x^2-8x-21$

Required polynomial = 5x² - 8x - 21

Answer 2

Answer:

$5 {x}^{2} - 8x + 21 = 0$

Step-by-step explanation:

$(x - 3)( x- \frac{-7}{5} ) = 0 \\ (x - 3)(5x + 7) = 0 \\ 5 {x}^{2} - 8x + 21 = 0$

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