Question

find the quadratic polynomial whose zeroes are 4and-2​

Answer 1

Answer:

$\large{\pink{\underline{\bold{\mathsf{x^2 - 2x - 8}}}}}$

Step-by-step explanation:

Given that:

The two zeroes are 4 and - 2.

Assumption:

Let α = 4 and β = - 2

By using the following formula, we can easily find the quadratic polynomial, that is,

k[x² - (α+β)x + (αβ)]

k[x² - (4 - 2)x + (4×-2)]

k[x² - (2)x + (-8)]

k[x² - 2x - 8]

Substituting k = 1;

∴ x² - 2x - 8

∴ The required quadratic polynomial is x² - 2x - 8.