Find the quadratic polynomial whose zeroes are 5/2√3 and 1/3√3
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Answered by
2
Hey!!!...Here is ur answer
quadratic polynomial = x^2-(sum of zeroes)x+multiplication of zeroes
=x^2-(5/2root3+1/3root3)x+5/2root3×1/3root3
= x^2-15+2/6root3x+5/18
=x^2-17/6root3x+5/18
Hope it will help you
quadratic polynomial = x^2-(sum of zeroes)x+multiplication of zeroes
=x^2-(5/2root3+1/3root3)x+5/2root3×1/3root3
= x^2-15+2/6root3x+5/18
=x^2-17/6root3x+5/18
Hope it will help you
Answered by
6
Heya !!!
Let Alpha = 5/2✓3 and beta = 1/3✓3
Therefore,
Sum of zeroes = (Alpha + Beta) = 5/2✓3 + 1/3✓3
=> 5(3✓3) + 1(2✓3) / (2✓3) (3✓3)
=> 15✓3 + 2✓3/ 18
=> 17✓3/18
=> 17✓3 / 2✓3 × 3✓3
=> 17/6✓3
And,
Product of zeroes = Alpha × Beta = 5/2✓3 × 1/3✓3 = 5/ 18
Therefore,
Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X²-(17/6✓3)X + 5/18
=> X²-17X/6✓3 + 5/18
HOPE IT WILL HELP YOU..... :-)
Let Alpha = 5/2✓3 and beta = 1/3✓3
Therefore,
Sum of zeroes = (Alpha + Beta) = 5/2✓3 + 1/3✓3
=> 5(3✓3) + 1(2✓3) / (2✓3) (3✓3)
=> 15✓3 + 2✓3/ 18
=> 17✓3/18
=> 17✓3 / 2✓3 × 3✓3
=> 17/6✓3
And,
Product of zeroes = Alpha × Beta = 5/2✓3 × 1/3✓3 = 5/ 18
Therefore,
Required Quadratic polynomial = X²-(Sum of zeroes)X + Product of zeroes
=> X²-(17/6✓3)X + 5/18
=> X²-17X/6✓3 + 5/18
HOPE IT WILL HELP YOU..... :-)
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