Question

Find the quadratic polynomial whose zeroes are 5+3 and 5-3

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

$\textbf{\large{\underline{\underline{\pink{Answer:-}}}}}$

The Quadratic polynomial,,,

$\mathrm{\implies{\boxed{\red{x^{2}-10x+16=0}}}}$

$\textit{\large{\underline{\underline{\pink{Step by step Explanation:-}}}}}$

$\textit{\underline{\green{Check,,}}}$

$\mathrm{x^{2}-10x+16=0}$

$\mathrm{a=1,,b=-10,,c=16}$

$\textit{\underline{Hence,,}}$

$\mathrm{b^{2}-4ac}$

$\mathrm{=(-10)^{2}-4\times{1}\times{16}}$

$\mathrm{=100-64}$

$\mathrm{=36}$

Because $\mathrm{(b^{2}-4ac)}$ is greater than Zero..

$\textit{\underline{Hence,,}}$

$\mathrm{x=\frac{-b\pm\sqrt{b^{2}-4ac}}{2a}}$

$\mathrm{=\frac{-(-10)\pm\sqrt{36}}{2\times{1}}}$

$\mathrm{=\frac{10\pm{6}}{2}}$

$\mathrm{=\frac{2(5\pm{3}}{2}}$

$\mathrm{=5\pm{3}}$

$\mathrm{x=5+3}$

and,,$\mathrm{x=5-3}$

so,, The Zeros are,,

$\mathrm{\implies{\boxed{\green{x=5+3}}}}$

$\mathrm{\implies{\boxed{\green{x=5-3}}}}$

$\textit{\underline{Hence proved,,}}$

So,, the polynomial will be,,

$\mathrm{\implies{\boxed{\green{x^{2}-10x+16=0}}}}$

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