Question

Find the quadratic polynomial whose zeroes are 5 and 3

Answer 1

formula:x²-(a+b)x+ab=0

substitute a=5;b=3 you'll get the answer

i.e x²-8x+15=0..

Answer 2

Answer:

Let a= 5 and b= -3

Sum of zeros = (a+b)=5+(-3)=2

Product of zeros = ab = 5×-3 = -15

So , the required polynomial is

×^2 - (a+b)× + ab = ×^2 - 2× + (-15)

= ×^2 -12× -15