find the quadratic polynomial whose zeros are -2root3 and -root3/2
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Hi ,
Let p and q are two roots of a
quadratic equation
Sum of the roots = -2√3 + ( -√3/2 )
p + q = ( -4√3 - √3 ) /2
= -5√3 / 2 ----( 1 )
Product of the roots = ( -2√3 ) ( -√3/2)
pq = 3 ----( 2 )
Required quadratic equation ,
x² - ( p + q ) x + pq = 0
x² - ( - 5√3/2 ) x + 3 = 0
x² + 5√3/2 x + 3 = 0
Multiply each term with 2 , we get
2x² + 5√3 x + 6 = 0
I hope this helps you.
:)
Let p and q are two roots of a
quadratic equation
Sum of the roots = -2√3 + ( -√3/2 )
p + q = ( -4√3 - √3 ) /2
= -5√3 / 2 ----( 1 )
Product of the roots = ( -2√3 ) ( -√3/2)
pq = 3 ----( 2 )
Required quadratic equation ,
x² - ( p + q ) x + pq = 0
x² - ( - 5√3/2 ) x + 3 = 0
x² + 5√3/2 x + 3 = 0
Multiply each term with 2 , we get
2x² + 5√3 x + 6 = 0
I hope this helps you.
:)
Aishez:
u rock
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