find the quadratic polynomial whose zeros are - 3 and 4
Answers
Answered by
13
Hey friend ..!! here's your answer
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Sum of zeroes = -3
Product of zeroes = 4
By using formula
sum of zeroes = -3 + 4 = 1
Product of zeroes = -3 × 4= -12
x^2 - (Sum of zeroes)x + (Product of zeroes) = 0
x^2 - (1)x + (-12) =0
x^2 - x - 12 =0
___________________
#Hope its help you dear#
☺
_________________________
Sum of zeroes = -3
Product of zeroes = 4
By using formula
sum of zeroes = -3 + 4 = 1
Product of zeroes = -3 × 4= -12
x^2 - (Sum of zeroes)x + (Product of zeroes) = 0
x^2 - (1)x + (-12) =0
x^2 - x - 12 =0
___________________
#Hope its help you dear#
☺
mrOogway:
Hey this is not correct
sorry....but you r wrong
my answer is 100% correct
and your answer is wrong
Hey!
what ??
You have entered the equation of a quadratic equation not quadratic polynomial. And, before answering something first check out completely and then answer! You fool!
u r wrong.....
Answered by
3
Let the quadratic polynomial be ax² + bx + c
∴ Sum of the zeros = -3 + 4 = 1
Also, Product of the zeros = -3 x 4 = -12
Thus the equation is
ax² + b - 12
∴ Sum of the zeros = -3 + 4 = 1
Also, Product of the zeros = -3 x 4 = -12
Thus the equation is
ax² + b - 12
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