find the quadratic polynomial whose zeros are 3 and minus -8 respectively
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Answered by
11
Sum of zeroes =s =3+(-8)=-5
Product of zeroes =p=3(-8)=-24
Quadratic eqn is
x²-sx+p=0
x²+5x-24=0
Product of zeroes =p=3(-8)=-24
Quadratic eqn is
x²-sx+p=0
x²+5x-24=0
Answered by
6
let α=3 and β=-8sum of zeros=3-8=-5product of zeros=3×{-8}=-24so required polynomial is = x²-{sum of zeroes}x+{product of zeros} = x²-{-5}x+{-24} = x²+5x-24
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