Question

find the quadratic polynomial whose zeros are 3 ,plus or minus√2​

Answer 1

Answer:

x²-(3+$\sqrt{2}$)x+3$\sqrt{2}$

Step-by-step explanation:

To make a quadratic equation the formula is =

k[x²-(α+β)x+αβ]

Answer 2

Answer:

This method is very easy

Step-by-step explanation:

follow the following formula

x^2 - (Sum of zeros)x +(product of zeros)=0

So, x^ - (3-root2)x + (3root2) =0

= x^2- (3-root2)x + 3root2=0

the above formula is only for quadratic equations