Question

find the quadratic polynomial whose zeros are under root 2 + 3 and under root 2 minus 3​

Answer 1

Answer:

alpha+beta= -b/a=root 2+3

alphabeta=c/a=2-3

p(x)=kxsquare-(alpha +beta)x+alphabeta

kxsquare-(root 2+3)x+(root2-3)

this will be the answer

please mark me as brainliest

Answer 2

Answer: x²-2√2x- 7

Step-by-step explanation:

Given,

Zeros of the quadratic polynomial are √2+3 and √2-3.

Sum of zeros = √2+3+√2-3

→ -b/a = 2√2

→ b/a = -2√2÷1

Product of zeros = (√2+3)(√2-3)

→ c/a = (√2)²-(3)²

→ c/a = 2-9

→ c/a = -7 ÷ 1

. ° . the required polynomial is

ax²+bx+c

→ (1)x² + (-2√2)x+(-7)

→ x²-2√2x- 7