Question

find the quadratic polynomial with given zeroes 2,-1

Answer 1

$given - \\ \: \: \: \: \: \alpha = 2 \: an d \: \beta = - 1 \\ \alpha + \beta = 2 + ( - 1) \\ = 2 - 1 \\ = 1 \\ and \: \alpha \times \beta = 2( - 1) \\ = - 2 \\ quadratic \: polynomial = {x}^{2} - ( \alpha + \beta )x +( \alpha \times \beta ) \\ = {x}^{2} - (1)x + ( - 2) \\ \\ = {x}^{2} - x - 2$
Heyy friend your answer is here

Answer 2

alpha =2 and beta= -1
now apha +beta =2+(-1)=1
alpha × beta=2×(-1)= -2
f(x) =k (x²-(alpha +beta)x + alpha × beta)
*(where K is any non zero real no)
f(x)= k(x²-x-2)
*(where K is any non zero real no)

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