Question

Find the quadratic polynomial with sum and product of its zeroes are 10 and -5 respectively

Answer 1

Step-by-step explanation:

$sum \:o f \:zeroes ( \alpha + \beta)=10 \\ product of zeroes( \alpha \beta ) = - 5 \\ \\ to \: \: find \: \:a \: \\ quadratic \: polynomial \: \\ the \: \: \: formula \: \: is \\ \: \: \: \: \: \: \: k \: ( {x}^{2} - ( \alpha + \beta )x + \alpha \beta \\ \: \: \: \: \: \: \: k \: ( {x}^{2} -10x + ( - 5) \: )\\ \: \: \: \: \: \: \: k \: ( {x}^{2} - 10x - 5) \\ \: \: \: \: \: \: \: \: \: \: \: ( \: \:let \: \: k \: \: be \: \: 1 \: ) \\ \: \: \: \: \: \: \: \: \: \: \:{x}^{2} - 10x - 5$

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