Pls answer this i will mark as brainlesttt
Answers
♠️(16) here displacement of the body is shown by R vector
R=√EC²+OE²
R=√3²+4²
R=√25
R=5m
distance travell is 3+4+6=13m
♠️(17) here circumference is 314m
2πr=314
3.14r=157
r=50m
here displacement is equal to diameter of circle
so we can said that
displacement=2r=2*50=100m
and distance travell is half perimeter of circle i.e πr = 3.14*50=157m
♠️(18). here displacement is shown by R vector
R=√OA²+AB²
R=√6²+8²
R=√100
R=10Km
distance travell is 6+8=14km
♠️(19) since speed and velocity are given by
speed=distance/time.
velocity=displacement/time
where distance is total path cover by object and displacement is shortest path cover by object, so speed depend upon distance and velocity depends upon displacement. both of two measurements of path are diffrent so speed is diffrent from velocity. so we can said that
speed > velocity (distance can be more then displacement)
speed = velocity (distance can be equal to displacement)
but displacement is no more than distance so speed is alway > = displacement because displacement is shortest path cover by object
♠️(20) displacement of the athletes is zero because it came back to its initial point and then
displacement = 0
distance traveled is two times that of perimeter
so
distance=4πr
=4*3.14*12
=150.72m
Answer:
Explanation:
(16)
Distance travelled = 3 + 4 + 6 = 13 m.
Displacement = √3² + 4² = √25 = 5 m.
(17)
Given, Circumference = 314 m.
2πr = 314
⇒ r = 50 m.
Distance movied in going A to B along circular path,
r = 1/2 * circumference
= 1/2 * 314
= 157 m.
Displacement = AB = 2r
= 2 * 50
= 100 m in east-west direction.
(18)
Distance travelled = 6 + 8 = 14 km.
Now,
Displacement = √8² + 6² = √100 = 10 km.
Therefore,
Displacement = 10 km.
(19)
No, the magnitude of the displacement is always less than or equal to the distance traveled.
(20)
Distance covered = 2(2πr) = 150.8 m
Since the athlete makes 2 complete rounds around the track, their final position is at the starting point, therefore their displacement is zero.
Hope it helps!