Question

find the quadratic polynomial with the given numbers as the sum and products of its zeroes respectively. (1) 1/4,-1​

Answer 1

Answer:4x^2-x-4

Step-by-step explanation: the quadratic formula

=k [x^2-x (sum ofor zeros)+(product of zeros )]

Sum of zeros=1/4,product of zeros =-1

=K [x^2-x (1/4)+(-1)]

Substitute K =4 then we get,

=4 [x^2-x (1/4)-1]

=4x^2-x-4

Answer 2

Answer:

4x² + 3x - 1

Step-by-step explanation:

Let a=¼ and b=-1.

a+b = -1 + ¼ = -¾.

a×b = -1 × ¼ = -¼.

Quadratic polynomial = k(x²-(a+b)x + (a×b))

= k( x²-(-¾)x + (-¼))

= k(x²+ ¾x - ¼)

=> k=4

= 4x² + 3x - 1