Question

Find the quadratic polynomials whose zeroes are
1)√3, -√3
2)6, -3​

Answer 1

Step-by-step explanation:

x^2-Sx+P = 0

1) S = √3-√3 = 0

P = √3* -√3 = -3

x^2 - 3 = 0

2) S = 6-3 = 3

P = -3*6 = -18

x^2-3x-18 = 0