Question

find the quadratic polynomials with -4,1 as the sum and product of its zero respectively
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Answer 1

Step-by-step explanation:

x^2-(-4)x+1

x^2+4x+1

Answer 2

answer:

${x }^{2} + 4x + x$

Step-by-step explanation:

as -4 is the sum of the zeroes and 1 is the product of zeroes

$k( {x}^{2} - sum \: of \: the \: zeroes \: x \: + product \: of \: the \: zeroes)$

therefore

$k( {x }^{2} - ( - 4)x + 1x)$

$k( {x}^{2} + 4x + x)$

as there is no fractions the value of k is 1

${x}^{2} + 4x + x$