Question

Find the quadratic polynomical if the zeros of it are sin 45°, Cos 45 respectively​

Answer 1

Answer:

sin 45° = 1/√2

cos 45°= 1/√2

sum of zeros = 1/√2 + 1√2 =√2

product of zeros = (1/√2)(1/√2) = 1/2

quadratic polynomial = k{x² + (sum of zeros)x - (product of zeros)}

= k{x² +√2x -1/2}

=k{(2x² + 2√2x -1)2}

k= 2

therefore , equation is

2x²+2√2x-1