Math, asked by krishbhagat732, 7 months ago

Find the quadratic root of the following equation x2-2x-24=0​

Answers

Answered by tanugarg62
2

Answer:

x²-2x-24=0

x²-2x-24=0=> x²-6x+4x-24=0

x²-2x-24=0=> x²-6x+4x-24=0=> x(x-6) +4(x-6)=0

x²-2x-24=0=> x²-6x+4x-24=0=> x(x-6) +4(x-6)=0=> (x+4)(x-6)=0

x²-2x-24=0=> x²-6x+4x-24=0=> x(x-6) +4(x-6)=0=> (x+4)(x-6)=0=> x+4=0 | x-6=0

x²-2x-24=0=> x²-6x+4x-24=0=> x(x-6) +4(x-6)=0=> (x+4)(x-6)=0=> x+4=0 | x-6=0=> x=-4 | x= 6

its the required roots

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