Question

find the quadretic polynomial whose product and sum of zeroes are 10 and -6 respectively ​

Answer 1

Step-by-step explanation:

x^2-(sum of zeroes)x+product of zero=0

x^2-(-6)x+(10)=0

x^2+6x+10 is the required quadratic polynomial.

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Answer 2

Answer:

x^2 + 4x - 60

Step-by-step explanation:

let the first zwro be alpha that is 10

second ---"-- bita that is (-6)

now thw sum is

alpha + bita = 10 +(-6)

= 4

and the product is

alpha ×bita = 10 × ( -6 )

= - 60

now putting value in the general formula ,

which gives

== > x ^2 + 4x - 60