find the quantity of water vapour at 100 degree celsius required just to melt 1kg of ice at 0 degree celsius. [please urgent]
Answers
Answered by
8
heat required to melt 1kg of ice at 0⁰C = 330 kJoules/kg * 1kg = 330 kJ
let the mass of watr vapour be = m kg
Heat present in water vapour at 100⁰C
= latent heat of vapourization + heat due to temperature
= 2260 kJ/kg * m kg + m kg * 4.18 kJ/kg/°C * 100°C
= m * [ 2260 + 418 ] k J
thus m = 330 / 2678 = 0.1232 kg = 123.2 grams
let the mass of watr vapour be = m kg
Heat present in water vapour at 100⁰C
= latent heat of vapourization + heat due to temperature
= 2260 kJ/kg * m kg + m kg * 4.18 kJ/kg/°C * 100°C
= m * [ 2260 + 418 ] k J
thus m = 330 / 2678 = 0.1232 kg = 123.2 grams
Similar questions