Question

{(x – y)(x + y) + (y – z)(y + z) + (z + x)(z – x)}​

Answer 1

Answer:

0

Step-by-step explanation:

= {(x – y)(x + y) + (y – z)(y + z) + (z + x)(z – x)}

= {(x^2 - y^2) + (y^2 - z^2) + (z^2 - x^2)}

= {x^2 - y^2 + y^2 - z^2 + z^2 - x^2}

= 0