Question

Find the quatric polynomial whose zero are 2 and -6 verify that coefficient of the following

Answer 1

Answer:

${x}^{2} + 4x - 12$

Step-by-step explanation:

Let the quadratic equation be in the form of ax^2 + bx + c.

$\alpha + \beta = - \frac{b}{a}$

$2 + ( - 6) = - \frac{b}{a}$

$- 4 = - \frac{b}{a}$

Therefore, a = 1, b = 4.

$\alpha \beta = \frac{c}{a}$

$2 \times - 6 = \frac{c}{a}$

$- 12 = \frac{c}{a}$

Therefore, a = 1, c = -12.

The quadratic equation formed is x^2 + 4x - 12.

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