Question

Find the qudratic polynomial the sum of whose zeroes is -10 and product of its zeroes is -39?

Answer 1

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Given that,

☯ Sum of the zeroes : α + ß = - 10

☯ Product of the zeroes : αß = - 39

We know that,

The form of quadratic polynomial is

↪ x² - (α + ß)x + αß = 0

Substitute the zeroes

➡ x² - (- 10)x + (- 39) = 0

➡ x² + 10x - 39 = 0

$\boxed{∴The \: Quadratic \: Polynomial \: is \: {x}^{2} + 10x - 39 = 0 }$

Step-by-step explanation:

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Answer 2

Solution

Given=》

Sum of zeros = -10

product of zeros = -39

To find =》

Quadratic polynomial

Formula we used=》

${x {}^{2} - ( \alpha + \beta )x + \alpha \beta }$

Explanation =》

x²-(-10)x+(-39)

= x²+10x-39

So quadratic polynomial is x²+10x-39