Find the quotient and the remainder when the smallest 7 digit number is divided by the greatest two digit number
Answers
Answer:
Hope this may help you
Step-by-step explanation:
9 999 999 = 3^2 x 239 x 4649
9 999 998 = 2 x 4 999 999
9 999 997 = 7 x 1 428 571
9 999 996 = 2^2 x 3 x 191 x 4363 -> divisible by 12 !
9 999 995 = 5 x 17 x 71 x 1657 -> divisible by 17 & 71 two 2 digit primes and 85
Answer:
What is the largest 7 digit number that is exactly divisible by 2 digit number?
All composite two digit numbers are obtained from multiplying two or more single digit numbers or a single digit number and a two digit prime number. Hence generally we can say that if we factorise a number by a single digit number two or more times or a two digit prime number, it is divisible by a two digit number.
9999999 -We can factorise it by number 3 two times. 3*3 = 9 which is not a two digit number. Any of the two digit prime numbers are also not a factor of this number. Hence this number is not divisible by two digit numbers.
9999998 - This number is divisible by 2 only. Any of the two digit prime numbers are also not a factor of this number. Hence this number is not divisible by two digit numbers.
9999997 - This number is divisible by 7 only. Any of the two digit prime numbers are also not a factor of this number. Hence this number is not divisible by two digit numbers.
9999996 - We can factorise this number by 2 two times and also by 3. Hence it is divisible by 12.
Therefore, the largest seven digit number which is divisible by two digit number is 9999996.