Math, asked by rasheedpokkath5568, 10 months ago

Find the radical center of the circle x2+y2-4x-6y+5=0,x2+y2-2x-4y-1=0,and x2+y2-6x-2y=0 and the equation and the length of the common chord of the circle x2+y2+4x-7=0,2x2+2y2+3x+5y-9=0,x2+y2+y=0

Answers

Answered by thandra1982
0

Answer:

the radical center of the circle x2+y2-4x-6y+5=0 ... x2+y2-6x-2y=0 and the equation and the length of the common chord of the circle x2+ y2+4x-7=0,2x2+2y2+3x+5y-9=0,x2+y2+y=0

Answered by PriyanshSingla
0

Answer:

Find the radical center of the circle x2+y2-4x-6y+5=0,x2+y2-2x-4y-1=0,and x2+y2-6x-2y=0 and the equation and the length of the common chord of the circle x2+y2+4x-7=0,2x2+2y2+3x+5y-9=0,x2+y2+y=0

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