Question

Find the radius and energyof third orbit of a hydrogen atom

Answer 1

Thus so

___________________________________@g __________________

. THE HYDROGEN HAS A ELECTRONIC CONFIGURATION. ( 1 )

THUS THE VALENCY OF HYDROGEN IS 1 .

AS IT HAS ONLY THE ' K ' SHELL WHICH HAS ONLY 1 ELECTRON THE ENERGY OF THE NUCLEUS TO HOLD IT IS MAXIMUM .

. THE RADIUS OF IT IS TE DISTANCE BETWEEN THE NUCLEUS AND THE VALENCE SHELL .

. SO IT DOES NT HAV A THIRD ORBIT .

. Hope it helps

Answer 2

Here, r =? n = 3, E =?

As r = n2h2/4∏2 mke2

r = 9 × (6.6 × 10-34)2 × 9 × 109/ [4 × (22/7) × (22/7) × 9.1 × 10-31 (1.6 × 10-19)2

= 4.775 × 10-10 m

= 4.775 Å

E = - 2∏2 mk2 e4/n2h2

On putting the standard values, we get

E = - 2.43 × 10-19 J