Find the radius and perimeter of a circle whose area is 77 cm^2
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Answered by
24
area of circle = 77 cm^2
=πr^2 = 77
= (22/7) x r^2 = 77
= r^2 = (77 x 7) / 22
= r^2 = 49/2
= r = 7/√2 cm
perimeter = 2πr = 2 x 22/7 x 7/√2
= 22√2 cm
=πr^2 = 77
= (22/7) x r^2 = 77
= r^2 = (77 x 7) / 22
= r^2 = 49/2
= r = 7/√2 cm
perimeter = 2πr = 2 x 22/7 x 7/√2
= 22√2 cm
Answered by
10
Radius of the circle is 7/√2 and perimeter of the circle is 22√2 cm.
- The area of the circle is given as 77 cm².
- Now area of circle is πr².
πr² = 77
r = 7/√2 cm.
- Now perimeter of the circle is the same as circumference of the circle.
- Circumference of the circle = 2πr = 2×22/7×7/√2 = 22√2 cm.
- Perimeter of the circle is 22√2 cm.
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