Question

Find the radius of a circle in which a central angle of 60° intercepts an arc of 132 cm . ( Take π = 22/7 )

Answer 1

Answer:

${\fbox{\huge{\tt{Solution\::}}}}$

Let "theta" be written as ¤

R=?

l (length of arc) = 132 cm

=> 132 = (¤/180) πr

=> 132 = 60/180 * 22/7 * r

=> 132 * 3 * 7/22 = r

=> 21 * 6 = r

=> r = 126 (Ans.)

Answer 2

${ \huge{\boxed{\tt {\color{red}{answer}}}}}$

Given,

Length of the arc = l = 132 cm

Central angle = θ = 60° = 60π/180 radian = π/3 radians

We know that,

r = l/θ

= (132) * (π / 3)

= (132) / [22 / 7 * 3]

= 126cm

Hence, the radius of the circle is 126 cm

Hope it's Helpful....:)