Question

find the radius of a circle who's circumstance is 5.28m
​

Answer 1

Answer:

3.36m

Step-by-step explanation:

2πr=5.28

r=5.28×7/22×2

r=3.36m

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Answer 2

$\large\underline{\frak{\qquad Given : \qquad}}$

• Find the radius of a circle who's circumference is 5.28 m.

$\large\underline{\frak{\qquad To\: Find : \qquad}}$

• Radius of circle = ?

$\large\underline{\frak{\qquad Solution : \qquad}}$

Let radius of circle be 'r' m.

☯ $\underline{\boldsymbol{According\: to \:the\: Question\:now :}}$

$:\implies \sf Circumference \: of \: circle = 2 \pi r$

$:\implies \sf 5.28 = 2 \times \dfrac{22}{7} \times r$

$:\implies \sf 2.64 = \dfrac{22}{7} \times r$

$:\implies \sf \dfrac{2.64 \times 7}{22} = r$

$:\implies \sf r = \dfrac{2.64 \times 7}{22}$

$:\implies \sf r = \dfrac{18.48}{22}$

$:\implies \underline{ \boxed{ \sf r = 0.84 \: m}}$

$\therefore\:\underline{\textsf{The radius of circle is \textbf{0.84 m}}}.$

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$\large\underline{\frak{\qquad Verification : \qquad}}$

$:\implies \sf 5.28 = 2 \times \dfrac{22}{7} \times r$

$:\implies \sf 5.28 = 2 \times \dfrac{22}{7} \times 0.84$

$:\implies \underline{ \boxed{ \sf 5.28 =5.28}}$

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$\large\underline{\frak{\qquad Extra \: brainly \: knowledge : \qquad}}$

$\boxed{\bigstar{\sf \ Cylinder :- }}\\ \\\sf {\textcircled{\footnotesize1}} Volume \ of \ Cylinder= \pi r^2 h \\ \\ \\ \sf {\textcircled{\footnotesize2}}\ Curved \ surface\ Area \ of \ cylinder= 2\pi r h\\ \\ \\ \sf {\textcircled{\footnotesize3}} Total \ surface \ Area \ of \ cylinder= 2\pi r (h+r)$

$\boxed{\bigstar{\sf \ Cone :- }}\\ \\\sf {\textcircled{\footnotesize1}} Volume \ of \ Cone= \dfrac{1}{3}\pi r^2 h \\ \\ \\ \sf {\textcircled{\footnotesize2}}\ Curved \ surface\ Area \ of \ Cone = \pi r l \\ \\ \\ \sf {\textcircled{\footnotesize3}} Total \ surface \ Area \ of \ Cone = \pi r (l+r) \\ \\ \\ \sf {\textcircled{\footnotesize4}} Slant \ Height \ of \ cone (l)= \sqrt{r^2+h^2}$

$\boxed{\bigstar{\sf \ Hemisphere :- }}\\ \\\sf {\textcircled{\footnotesize1}} Volume \ of \ Hemisphere= \dfrac{2}{3}\pi r^3 \\ \\ \\ \sf {\textcircled{\footnotesize2}}\ Curved \ surface\ Area \ of \ Hemisphere = 2 \pi r^2 \\ \\ \\ \sf {\textcircled{\footnotesize3}} Total \ surface \ Area \ of \ Hemisphere = 3 \pi r^2$

$\boxed{\bigstar{\sf \ Sphere :- }}\\ \\\sf {\textcircled{\footnotesize1}} Volume \ of \ Sphere= \dfrac{4}{3}\pi r^3 \\ \\ \\ \sf {\textcircled{\footnotesize2}}\ Surface\ Area \ of \ Sphere = 4 \pi r^2$

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