Question

Find the radius of a circle whose area is equal to the sum of areas of two circles with radii 6 cm and 8 cm​

Answer 1

Answer:

Step-by-step explanation:

radius of first circle is = pi(r)square =pi*6*6=36pi

radius of second circle = pi*8*8=64pi

area of required circle is = 100pi

radius r =root 100=10cm

Answer 2

Answer:

Step-by-step explanation:

Sum of areas of two circles with given radius=$\pi r^2+\pi R^{2}$

                                                             =22/7(36+64)

                                                             =314.3 cm^2

Given,

Area of circle=sum of another two circe's area

$\pi r^{2}$ = 314.3

22/7*r^2=314.3

r^2=100<aprox>

r=10 cm