Find the radius of an arc of radius 3m which subtends an angleof 45° at the center of the circle
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Given:
Area of minor sector, A=77 cm
2
Angle subtended by sector, θ=45
o
To find: Radius r
Area of minor sector subtending angle of θ
o
at center of a circle of radius r is given by A=
360
θ
×πr
2
Substituting values, we get:
77=
360
45
×πr
2
r≈
45×22/7
77×360
∵π≈22/7
r=14 cm
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