find the radius of nucleus of an atom having atomic mass number equal to 125
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R=Rⁿ×a^1/3
so 1.2×10^-15×5 because rⁿ is an Empricial constant
6×10^-15 answer
so 1.2×10^-15×5 because rⁿ is an Empricial constant
6×10^-15 answer
Rojashwee23:
not ans
2.7×10^-14
what us the ans
see above
but ❓❓
i don't know
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