Question

Find the radius of the circle whose area is equal to the sum of the area of three circle with radii 2, 5 6 cm​...

Answer 1

radius of first circle =2cm

area =22/7×2×2=88/7=12.57

radius of second circle =5cm

area=22/7×5×5 = 550/7=78.57

radius of third circle =6cm

area = 22/7×6×6=792/7=113.14

Total area =12.57+78.57+113.14=204.28

radius of circle :

204.28=22/7×r×r

1429.96=22×r×r

r×r=1429.96/7

=64.99

r=8.05

Answer 2

$\huge\mathcal\color{teal} Given:-$

✏ Radius of three circles = 2 cm, 5 cm & 6 cm.

✏ Area of bigger circle = Sum of the areas of three circles with radii 2, 5 & 6 cm

$\huge\mathcal\color{teal} To - Find :$

★ Radius of the big circle

$\huge\mathcal\color{teal} Solution :-$

Radius _________★★

⟹ r1 = 2 cm

⟹ r2 = 5 cm

⟹ r3 = 6 cm

☞ Area of circle = π r^2

Now,

★Area of bigger circle = Area of 1st circle + Area of 2nd circle + Area of 3rd circle

⟹ πR^2 = π ( 2)^2 + π ( 5)^2 + π ( 6)^2

⟹ R = √ 65

⟹ R = 8.0622 cm

${\huge{\mathcal{\pink{Hope \ It's \ Helpful..!!!}}}}$