Question

find the radius of the circle whose center is (3,2) and passes through (-5,6)​

Answer 1

Equation of circle with centre (h,k) and radius r is given by

 (x-h)²+(y-k)²=r

Distance between 2 points (√[(x₂-x₁)²+(y₂-y₁)²]

Coordinates of center are (3,2)

Since it passes through (-5,6)

Radius of circle is the distance between two points (3,2) (-5,6)

=(√[(x₂-x₁)²+(y₂-y₁)²]

r=√[(3+5)²+(2-6)²]

=√(64+16)

=√(80)=(4x2x2x5)=4√ 5 units

Answer 2

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Equation of circle with centre (h,k) and radius r is given by

 (x-h)²+(y-k)²=r

Distance between 2 points (√[(x₂-x₁)²+(y₂-y₁)²]

Coordinates of center are (3,2)

Since it passes through (-5,6)

Radius of circle is the distance between two points (3,2) (-5,6)

=(√[(x₂-x₁)²+(y₂-y₁)²]

r=√[(3+5)²+(2-6)²]

=√(64+16)

=√(80)=(4x2x2x5)=4√ 5 units

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