tan (A + B)= m, tan ( A - B) = n then find cot 2B
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Answer:
1 + mn / m - n
Step-by-step explanation:
Given--->
tan( A + B ) = m , tan ( A - B ) = n
To find--->
Value of Cot 2B
Solution--->
2 B = B + B
= A + B - A + B
2 B = ( A + B ) - ( A - B )
Taking tan both sides
tan 2 B = tan { (A + B ) - ( A - B ) }
tan ( A + B ) - tan ( A - B ) = ---------------------------------------
1 + tan (A + B ) tan ( A - B )
m - n
tan 2B = --------------
1 + m n
We know that
Cot θ = 1 / tanθ
So
Cot 2B = 1 / tan2B
Cot 2B = (1 + mn ) / ( m - n)
Additional information--->
1)Sin (A + B ) = SinA CosB + CosA SinB
2)Sin (A - B ) = SinA CosB - CosA SinB
3)Cos (A + B) = CosA CosB - SinA SinB
4)Cos (A - B ) = CosA CosB + SinA SinB
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