Question

Find the radius of the circle whose centre is (3, 2) and passes through (–5, 6).

Answer 1

$\mathfrak{\huge{\blue{\underline{\underline{Answer :}}}}}$

Equation of circle with centre (h,k) and radius r is given by

 (x-h)²+(y-k)²=r

Distance between 2 points (√[(x₂-x₁)²+(y₂-y₁)²]

Coordinates of center are (3,2)

Since it passes through (-5,6)

Radius of circle is the distance between two points (3,2) (-5,6)

=(√[(x₂-x₁)²+(y₂-y₁)²]

r=√[(3+5)²+(2-6)²]

=√(64+16)

=√(80)=(4x2x2x5)= 4√ 5 units

$<marquee>$Hope It Will Help.❤️

Answer 2

Step-by-step explanation:

I HOPE IT'S HELPFUL FOR YOU. ☺☺