Find the radius of the circle whose centre is (3, 2) and passes through ( - 5, 6).
Answers
Answered by
31
Equation of circle with centre (h,k) and radius r is given by
(x-h)²+(y-k)²=r
Distance between 2 points (√[(x₂-x₁)²+(y₂-y₁)²]
Coordinates of center are (3,2)
Since it passes through (-5,6)
Radius of circle is the distance between two points (3,2) (-5,6)
=(√[(x₂-x₁)²+(y₂-y₁)²]
r=√[(3+5)²+(2-6)²]
=√(64+16)
=√(80)=(4x2x2x5)=4√ 5 units
(x-h)²+(y-k)²=r
Distance between 2 points (√[(x₂-x₁)²+(y₂-y₁)²]
Coordinates of center are (3,2)
Since it passes through (-5,6)
Radius of circle is the distance between two points (3,2) (-5,6)
=(√[(x₂-x₁)²+(y₂-y₁)²]
r=√[(3+5)²+(2-6)²]
=√(64+16)
=√(80)=(4x2x2x5)=4√ 5 units
Answered by
5
Answer:
4√5
Step-by-step explanation:
ANSWER
Radius of the circle whose centre is (3,2) and passes through (−5,6) is the distance between (3,2) and (−5,6)
= √[(−5−3)²+(6−2)²]
= (−8)² +(4)²
=√ (64+16)
= √80
=4 √5 Units.
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